+0

# trig question

0
28
1

In right triangle $ABC$ with $\angle B = 90^\circ$, we have $\sin A = 2\cos A$. What is $\tan A$?

Guest Nov 21, 2018

#1
+3152
+1

$$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$$

Rom  Nov 21, 2018
#1
+3152
+1
$$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$$