trig question

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In right triangle $ABC$ with $\angle B = 90^\circ$, we have $\sin A = 2\cos A$. What is $\tan A$?

Guest Nov 21, 2018

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Best Answer

$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$

Rom Nov 21, 2018

Rom · Answer 1 · 2018-11-21T06:43:26

$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$

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