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# trig question

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In right triangle $ABC$ with $\angle B = 90^\circ$, we have $\sin A = 2\cos A$. What is $\tan A$?

Nov 21, 2018

#1
+3899
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$$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$$

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Nov 21, 2018

#1
+3899
+1
$$\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2$$