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In right triangle $ABC$ with $\angle B = 90^\circ$, we have $\sin A = 2\cos A$. What is $\tan A$?

 Nov 21, 2018

Best Answer 

 #1
avatar+6046 
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\(\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2\)

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 Nov 21, 2018
 #1
avatar+6046 
+1
Best Answer

\(\tan(A) = \dfrac{\sin(A)}{\cos(A)} = \\ \dfrac{2\cos(A)}{\cos(A)} = 2\)

Rom Nov 21, 2018

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