+2668 Recall that \(\sin = {\text{opposite} \over \text{hypotenuse}}\)
Because we applying sin to A, we have \(CB \over AB\).
Can you take it from here?
Also, that isn't a triangle, because \(9^2 + 6^2 ≠ 15^2\). The rule for the triangle side length does not hold true here either, because \(9+6\) is not greater than 15.
