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Find sin BAC.

 

 May 4, 2022
 #1
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Recall that \(\sin = {\text{opposite} \over \text{hypotenuse}}\)

 

Because we applying sin to A, we have \(CB \over AB\).

 

Can you take it from here?

 

Also, that isn't a triangle, because \(9^2 + 6^2 ≠ 15^2\). The rule for the triangle side length does not hold true here either, because \(9+6\) is not greater than 15. 

 May 4, 2022

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