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In right triangle BCD with angle D = 90 degrees, we have BC = 9 and BD = 8. Find sin B.

 Jan 10, 2022
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 Find sin B.

 

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\(sin\ B=\frac{\sqrt{9^2-8^2}}{9}=\frac{\sqrt{17 }}{9}=\color{blue}0.45812\)

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 Jan 10, 2022

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