4^3x=16^x+1
x = 0.0327345
x = 1.68478
Is this supposed to be.........
4^(3x)=16^(x+1) ??? if so, note that 16 = 4^2 .....so we have
4^(3x) = [4^2]^(x + 1)
4^(3x) = 4^(2x + 2) and since the bases are alike, we can solve for the exponents
3x = 2x + 2 subtract 2x from each side
x = 2
