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In triangle $ABC$, we have $\angle A = 90^\circ$ and \(\sin B = \frac{4}{9}\). Find $\cos C$.

 Jan 12, 2022
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Find cos C.

 

Hello Guest!

 

If the sin B = 4/9 in a right triangle, then the ratio of the sides is

a: b: c = 9: 4: 3.

So is

cos C = 4/9

laugh  !

 Jan 12, 2022

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