does anyone remember how to compute the integral from 0 to +infinity of sin(at)/(1+t^2), with a>0? Thanks
Use integration by parts. Your two functions are sin(at) and 1/(1+t^2)
Integral of 1/(1+t^2) = arc tan t.
you will get Integral = sin(at).arctan (t) - Integral ( 1/(1+t^2).a cos(at) ) dt ....keep going...
sure u can complete this.......
