Suppose cos (θ) = -0.6. What is the value of cos (pi + θ)? Anyone who can write out the steps to this problem will be awesome. It sounds like an easy question, but I am stumped.
Suppose cos (θ) = -0.6. What is the value of cos (pi + θ)? Anyone who can write out the steps to this problem will be awesome. It sounds like an easy question, but I am stumped.
It appears that you are using "radians" instead of "degrees".
Cos(theta)=-.6, therefore the inverse cosine of Theta is=2.2143.... + 3.141592653=5.355892653
Therefore, Cos(5.355892653)=.6, which is your answer.
Suppose cos (θ) = -0.6. What is the value of cos (pi + θ)? Anyone who can write out the steps to this problem will be awesome. It sounds like an easy question, but I am stumped.
It appears that you are using "radians" instead of "degrees".
Cos(theta)=-.6, therefore the inverse cosine of Theta is=2.2143.... + 3.141592653=5.355892653
Therefore, Cos(5.355892653)=.6, which is your answer.
+130536 Using the cosine inverse, we have
cos-1(.-.06) = theta = about 126.87°.....however......this could also be a 3rd quadrant angle =
180 + (180 - 126.87) = about 233.13°
And substituting 180 for "pi," we have
And cos(pi + theta) = cos(180 + theta) = -cos(theta) = -cos(126.87) = 0.6 ....and....
cos(180 +233.13) = -cos(233.13) = 0.6
