+1904 How do I convert the complex number \(\sqrt{2}i\) to polar form and how do I convert it back to a compkex number?
+118608
How do I convert the complex number to polar form and how do I convert it back to a complex number?
\(\sqrt2 i\)
I muffle through these I am sure there is a better technique but this is a very easy one. :)
\(\sqrt{2}\:i=\sqrt{2}(0+1i)\\ cos\theta=0\;\;\;\;\;sin\theta=+1\\ \theta=\frac{\pi}{2}\\ \sqrt{2}\:i=\sqrt{2}(cos\frac{\pi}{2}+isin\frac{\pi}{2})=\sqrt2e^{i\pi/2}\\ \)
Converting it back is dead simple, just do the same thing backwards :)
