1.
Given f(x)=4x2+19x−5 and g(x)=4x2−x .
What is (fg)(x)?
x+5x where x≠0, 1/4
−x19x−5 where x≠0, 5/19
xx+5 where x≠0, 5
−19x+5x where x≠0, 1/4
2.
Given f(x)=2x2+3x and g(x)=5x2−2x−6 .
What is (f+g)(x) ?
10x2+x+6
3x2−5x−6
7x2+x−6
−3x2+5x+6
+128408 I think the first one might be
(f/g)(x) = 4x^2 + 19x - 5 (4x - 1) (x + 5) x + 5
____________ = _____________ = ____________
4x^2 - x x ( 4x - 1) x
With the restrictions that x not equal to 0 or 1/4
Second one
(f + g) (x) = [ 2x^2 + 3x ] + [5x^2 -2x - 6 ] = 7x^2 + x - 6
