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1.

Given f(x)=4x2+19x−5 and g(x)=4x2−x .

What is (fg)(x)?

 

  • x+5x where x≠0, 1/4

  • −x19x−5 where  x≠0, 5/19

  • xx+5   where x≠0, 5

  • −19x+5x where x≠0, 1/4

2. 

Given f(x)=2x2+3x and g(x)=5x2−2x−6 .

What is (f+g)(x) ?

 

  • 10x2+x+6

  • ​ 3x2−5x−6 ​

  • 7x2+x−6

  • ​ −3x2+5x+6 ​

 Mar 22, 2018
 #1
avatar+100595 
+1

I think the first one might be

 

(f/g)(x) =        4x^2 + 19x  - 5           (4x - 1) (x + 5)              x  +  5

                      ____________   =   _____________  =    ____________

                        4x^2  - x                    x ( 4x - 1)                         x

 

With the restrictions that x  not equal to  0  or  1/4

 

 

Second one

 

(f + g) (x)  =  [ 2x^2 + 3x ] + [5x^2  -2x  - 6 ]  =   7x^2 + x - 6

 

 

 

cool cool cool

 Mar 23, 2018

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