+466 Solve, given that (0o < x < 360o): 2 sin2 x - 3 sin x + 1 = 0
I have to solve for x, and x has to be an angle. 
+128597 2 sin^2 x - 3 sin x + 1 = 0 factor as :
(2sinx - 1) (sinx - 1) = 0
Now, either
2sinx - 1 = 0 → sinx = 1 / 2 and this occurs at 30° and 150° on the given interval
OR
sinx - 1 = 0 → sin x = 1 and this occurs at 90°
Here's a graph of the solutions.....https://www.desmos.com/calculator/exqk4ustum
+118608 Hi SHADES,
I as well as a guest, answered that same question somewhere else.
Please do not ask the same question in 2 different places!
It often means that you get 2 identical answers and someone else gets no answer to their question.!
Please follow the guidelines if you want to repost a question!
http://web2.0calc.com/questions/instructions-on-reposting_1
Thank you :)
+466 The guest didn't help me at all, so I had to post my question again so that I could get an answer... You didn't answer till later...
+118608 That is fine Shades, I have not problem with you reposting
BUT
You need to do it the way you have been asked.
State that your question has not been answered yet and include the address of you question OR a link to it.
DO NOT rewrite the whole question all over again so that there are two complete identical questions on the forum.
Thank you :)
