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Using Elimination Method, How do I solve

4x + 6y = 6 (1)

3x - 3y =12 (2)

 Jun 22, 2016

Best Answer 

 #1
avatar+129843 
+5

4x + 6y = 6    (1)
3x - 3y =12   (2)       multiply this equation by 2  →   6x - 6y   = 24    (3)

 

Add equation 3 to equation 1

 

10x   =  30        divide both sides by 10

 

x  = 3    substitute this into any equation to find y  [ I'll use 2 ]

 

3(3) - 3y   = 12

 

9 - 3y   = 12       add 3y to both sides, subtract 12 from both sides

 

-3 =  3y               divide both sides by  3

 

-1  = y

 

So   {x , y }   =   { 3, -1 }

 

 

 

cool cool cool

 Jun 22, 2016
 #1
avatar+129843 
+5
Best Answer

4x + 6y = 6    (1)
3x - 3y =12   (2)       multiply this equation by 2  →   6x - 6y   = 24    (3)

 

Add equation 3 to equation 1

 

10x   =  30        divide both sides by 10

 

x  = 3    substitute this into any equation to find y  [ I'll use 2 ]

 

3(3) - 3y   = 12

 

9 - 3y   = 12       add 3y to both sides, subtract 12 from both sides

 

-3 =  3y               divide both sides by  3

 

-1  = y

 

So   {x , y }   =   { 3, -1 }

 

 

 

cool cool cool

CPhill Jun 22, 2016
 #2
avatar+8 
+5

This was much appreciated

HarderThanTrigg  Jun 22, 2016

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