Find the volume of the square pyramid, given its slant height
The volume of a square pyramid is found using the formula: V = (1/3) * base area * height, or V = (1/3) * s² * h, where 's' is the side length of the square base and 'h' is the height of the pyramid.
Not too hard, all we need is the height. Drop a perpendicular from the apex to the center of the base. That's the height. From that center point, draw a line across the square base over to the bottom of the slant height. That's one leg of a right triangle and the slant height is its hypotenuse. From those two sides, we can find the third side which is the height. Thank you, Pythagoras.
Remember that in a right triangle c2 = a2 + b2 which means that b2 = c2 – a2
(height)2 = 302 – 162 = 900 – 256 = 644
height = sqrt(644) = 25.377
V = (1/3) • (32)2 • 25.377 = 8662.02 cm3
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