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avatar+37 

16x being raised to (2n+1)

bingby  Apr 18, 2017
 #1
avatar+90023 
0

16x^(2n + 1)  =

 

16x^(2n)*x

 

 

cool cool cool

CPhill  Apr 18, 2017
 #2
avatar+37 
0

What about 16x being raised to 2(n+1)

bingby  Apr 18, 2017
 #3
avatar+90023 
0

(16x)^(2n + 1)  =

 

(16x)^(2n) * 16x  \

 

[(16x)^2]^n * 16x  =

 

[256 x^2]^n * 16x

 

 

cool cool cool

CPhill  Apr 18, 2017
 #4
avatar
0

Try using this website next time.

https://goo.gl/t4IKhr

The answer is 16x being raised to (2n+1) like he said.....

Guest Apr 18, 2017

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