what is 14^2-(5-3)^2+(6-2)^2
I NEED HELP WITH THIS IM ONLY IN 6th GRADE!!!!
just do order of operations GEMA or PEMDAS paren, exponets,multi, divis,add,subtract
14^2 = 14 x 14 = 196
(5-3)^2 = (2)^2 = 2 x 2 = 4
(6-2)^2 = (4)^2 = 4 x 4 = 16
14^ - (5-3)^2 + (6-2)^2 becomes:
196 - 4 + 16
= 192 + 16
= 208
When solving problems like these, always do what's inside parentheses first.
Do you wanna do my collage math I'm only in 9th Grade. Are you up to do that?