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what is 14^2-(5-3)^2+(6-2)^2

 

I NEED HELP WITH THIS IM ONLY IN 6th GRADE!!!!

 Oct 7, 2014

Best Answer 

 #2
avatar+23247 
+5

14^2  =  14 x 14  =  196

(5-3)^2  =  (2)^2  =  2 x 2  =  4

(6-2)^2  =  (4)^2  =  4 x 4  =  16

14^ - (5-3)^2 + (6-2)^2   becomes:

196  -  4  +  16

 =  192  +  16  

 =  208

When solving problems like these, always do what's inside parentheses first.

 Oct 7, 2014
 #1
avatar
+5

just do order of operations GEMA or PEMDAS paren, exponets,multi, divis,add,subtract

 Oct 7, 2014
 #2
avatar+23247 
+5
Best Answer

14^2  =  14 x 14  =  196

(5-3)^2  =  (2)^2  =  2 x 2  =  4

(6-2)^2  =  (4)^2  =  4 x 4  =  16

14^ - (5-3)^2 + (6-2)^2   becomes:

196  -  4  +  16

 =  192  +  16  

 =  208

When solving problems like these, always do what's inside parentheses first.

geno3141 Oct 7, 2014
 #3
avatar+472 
0

Do you wanna do my collage math I'm only in 9th Grade. Are you up to do that?

 Oct 8, 2014

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