wouldnt it easier to solve it this way $${\frac{\left({\frac{{\mathtt{14}}}{{\mathtt{1}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}{{\mathtt{4}}}} = {\frac{{\mathtt{11}}}{{\mathtt{3}}}} = {\mathtt{3.666\: \!666\: \!666\: \!666\: \!666\: \!7}}$$ with the calculater?
$$Turn $14\frac{2}{3}$ into an improper fraction = $\frac{44}{3}$\\\\
Divide this by 4 to get $\frac{11}{3}$ or $3\frac{2}{3}$$$
wouldnt it easier to solve it this way $${\frac{\left({\frac{{\mathtt{14}}}{{\mathtt{1}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}{{\mathtt{4}}}} = {\frac{{\mathtt{11}}}{{\mathtt{3}}}} = {\mathtt{3.666\: \!666\: \!666\: \!666\: \!666\: \!7}}$$ with the calculater?