I will assume that x and X are meant to be the same.
$$3(x+y)\div 12x \qquad where\:\:y=5\\\\ =3(x+5)\div 12x\\\\ =\dfrac{3(x+5)}{12x}\\\\ \mbox{divide top and bottom by 3}\\\\ =\dfrac{1(x+5)}{4x}\\\\ =\dfrac{x+5}{4x}\\\\$$
I will assume that x and X are meant to be the same.
$$3(x+y)\div 12x \qquad where\:\:y=5\\\\ =3(x+5)\div 12x\\\\ =\dfrac{3(x+5)}{12x}\\\\ \mbox{divide top and bottom by 3}\\\\ =\dfrac{1(x+5)}{4x}\\\\ =\dfrac{x+5}{4x}\\\\$$