What is i^35?

Simplify the following:
i^35

i^35  =  i^(4×8+3)  =  (i^4)^8 i^3:
(i^4)^8 i^3

i^3 = i^2×i = (-1) i = -i:
(i^4)^8 -i

i^4 = (i^2)^2 = (-1)^2 = 1:
-1^8 i

1^8 = 1:
Answer: |   -i