What is the 1st, 2nd, and 3rd integers?

Let the smallest integer be n.  Then the next two are n+2 and n+4, so the sum of all three is:

n + n+2 + n+4 or 3n + 6.

 

We are told that this is 195:

3n + 6 = 195

 

Subtract 6 from both sides:

3n = 189

 

Divide both sides by 3:

n = 189/3 = 63.

 

So the three numbers are 63, 65 and 67.

 

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