What is the equation of the line which passes through (3,1) and (-2,-4)?

Hello anonymous and CPhill !

What is the equation of the line which passes through (3,1) and (-2,-4)?

y1 = 1   x1 = 3   y2 = -4   x2 = -2

m = (y2 - x2) / (y1 - x1) = (-4 - (-2)) / (1 - 3) = -2 / -2

m = 1

y = mx + b

y1 = m * x1 +b

b = y1 - m * x1 = 1 - 1 * 3 = 1 - 3

b = - 2

y = ƒ(x) = mx + b

y = ƒ(x) = x - 2

The equation of the line which passes through (3,1) and (-2,-4) is

y = ƒ(x) = x - 2

Greetings   :- )

See what i just did, here : 

http://web2.0calc.com/questions/what-is-the-of-the-line-that-passes-through-the-points-2-1-and-4-5-in-the-cartesian-coordinate-plane