If y=2x + 1/3,
x=2y + 1/3
2y=x - 1/3
y=(x - 1/3)/2
Inverse: (y=) x/2 - 1/6
If y=(2x+1)/3,
x=(2y+1)/3
3x=2y+1
2y=3x-1
Inverse: y=(3x-1)/2
Hope this helps!
Di you mean $$2x+\frac{1}{3}$$
or do you mean $$\frac{2x+1}{3}$$ ? If this is what you mean then you need to use brackets.
If y=2x + 1/3,
x=2y + 1/3
2y=x - 1/3
y=(x - 1/3)/2
Inverse: (y=) x/2 - 1/6
If y=(2x+1)/3,
x=(2y+1)/3
3x=2y+1
2y=3x-1
Inverse: y=(3x-1)/2
Hope this helps!