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What is the measure of ∠J to the nearest degree?

45°

55°

70°

83°

 

ssarbin14  May 4, 2018

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 #2
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7 / sin(80) = 5 / sin(J)

7 / 0.9848 = 5 / sin(J)   cross multiply

7*sin(J) =0.9848*5

7*sin(J) =4.924             divide both sides by 7

sin(J) =4.924 / 7

J = Arcsin(4.924 /7) =44.70 = ~45 degrees.

Guest May 4, 2018
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 #2
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Best Answer

7 / sin(80) = 5 / sin(J)

7 / 0.9848 = 5 / sin(J)   cross multiply

7*sin(J) =0.9848*5

7*sin(J) =4.924             divide both sides by 7

sin(J) =4.924 / 7

J = Arcsin(4.924 /7) =44.70 = ~45 degrees.

Guest May 4, 2018

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