What is the pOH if the (OH-) is 1 x 10 -10 ?

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Guest Nov 14, 2014

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Best Answer

pOH = - log [OH^-]

pOH = - log [1.00 x 10^-10] = - ( - 10) = 10

pOH = 10

BrittanyJ Nov 14, 2014

BrittanyJ · Answer 1 · 2014-11-14T01:31:33

pOH = - log [OH^-]

pOH = - log [1.00 x 10^-10] = - ( - 10) = 10

pOH = 10