what is the product 8 to the third power times 4 to the second power times 16 written as 2 to the what power?
Write each of the factors with a base of 2:
8 = 2^3 ---> so, 8^3 becomes (2^3)^3 = 2^9 When you have an exponent to an exponent,
4 = 2^2 ---> so, 4^2 becomes (2^2)^2 = 2^4 multiply the exponents.
16 = 2^4
(8^3) x (4^2) x (16) = (2^9) x (2^4) x (2^4) = 2^17 When you are multiplying numbers with the same
base, add the exponents.
Write each of the factors with a base of 2:
8 = 2^3 ---> so, 8^3 becomes (2^3)^3 = 2^9 When you have an exponent to an exponent,
4 = 2^2 ---> so, 4^2 becomes (2^2)^2 = 2^4 multiply the exponents.
16 = 2^4
(8^3) x (4^2) x (16) = (2^9) x (2^4) x (2^4) = 2^17 When you are multiplying numbers with the same
base, add the exponents.