+0  
 
0
1082
2
avatar

what is the product 8 to the third power times 4 to the second power times 16 written as 2 to the what power?

 Oct 20, 2014

Best Answer 

 #1
avatar+23254 
+5

Write each of the factors with a base of 2:

8 = 2^3   --->   so, 8^3  becomes  (2^3)^3  =  2^9         When you have an exponent to an exponent,

4 = 2^2   --->   so, 4^2  becomes  (2^2)^2  =  2^4          multiply the exponents.

16 = 2^4

(8^3) x (4^2) x (16)  =  (2^9) x (2^4) x (2^4)  =  2^17   When you are multiplying numbers with the same

                                                                                     base, add the exponents.

 Oct 20, 2014
 #1
avatar+23254 
+5
Best Answer

Write each of the factors with a base of 2:

8 = 2^3   --->   so, 8^3  becomes  (2^3)^3  =  2^9         When you have an exponent to an exponent,

4 = 2^2   --->   so, 4^2  becomes  (2^2)^2  =  2^4          multiply the exponents.

16 = 2^4

(8^3) x (4^2) x (16)  =  (2^9) x (2^4) x (2^4)  =  2^17   When you are multiplying numbers with the same

                                                                                     base, add the exponents.

geno3141 Oct 20, 2014
 #2
avatar
0

2^17

nailed it.

 Oct 20, 2014

1 Online Users