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what is the square root of I???is it simply sqrt I?

wgunningham  Apr 18, 2017
 #1
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sqrt(i) = (-1)^(1/4)

Guest Apr 18, 2017
 #2
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Further:  \((-1)^{1/4} \rightarrow e^{i\pi/4}\rightarrow \frac{\sqrt2}{2}(1+i)\)

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Alan  Apr 18, 2017

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