What is x in this equation: 21^2=(21x)^2+(9x)^2

0

509

1

What is x in this equation: 21^2=(21x)^2+(9x)^2

Guest Mar 10, 2015

0 users composing answers..

Best Answer

+23246

+5

21² = (21x)² + (9x)²

441 = 441x² + 81x²

441 = 522x²

441/522 = x²

49/58 = x²

x = ±√(49/58)

geno3141 Mar 10, 2015

1⁺⁰ Answers

+23246

+5

Best Answer

21² = (21x)² + (9x)²

441 = 441x² + 81x²

441 = 522x²

441/522 = x²

49/58 = x²

x = ±√(49/58)

geno3141 Mar 10, 2015

0 Online Users