What is y in 6)2y+3)-3(y-5) = 0

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Guest Oct 6, 2014

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Best Answer

multiply the coefficents = (12y+18)-(3y-15)

then add like terms = 9y+3=0 and seperate the y and subtract 3 to place it on the other side...

9y=-3 now divide by 9

y=-1/3

Guest Oct 6, 2014

Guest · Answer 1 · 2014-10-06T04:00:25

multiply the coefficents = (12y+18)-(3y-15)

then add like terms = 9y+3=0 and seperate the y and subtract 3 to place it on the other side...

9y=-3 now divide by 9

y=-1/3