+0  
 
0
410
1
avatar+36 

Which expression is equal to  tan^2ϴ cscϴ+(1/sin(ϴ))

a. sec^3 ϴ

b. csc^3 ϴ

c. csc^2 ϴ sec ϴ

d. sec^2 ϴ cscϴ

nlbradshaw0430  Apr 13, 2017
 #1
avatar+88899 
+2

tan^2 θ  * csc θ   +  (1 / sin θ)

 

[sin^2 θ / cos^2 θ] * (1/ sin θ) + (1 /sin θ)     factor out  1 / sin θ

 

1 / sin θ  [  sin ^2 θ / cos^2θ   +  1 ]  =

 

1/sin θ [  (sin^2θ + cos^2θ] / cos^2θ  =

 

1/sin θ  [ 1 / cos^2 θ ]  =

 

cscθ * sec^2 θ  =

 

sec^2 θ csc θ

 

 

 

cool cool cool

CPhill  Apr 13, 2017

30 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.