Which of the following functions has the solution (3, -2)?

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Which of the following functions has the solution (3, -2)?

Select all that apply.

(1) y=-2x+4

(2) f(x)=-x+2

(3) f(x)=-23x

(4) f(x)=3x−2

(5) f(x)=4x+11

(6) f(x)=6x−20

$\begin{array}{|rcll|} \hline (3, -2) \quad \text{or } \\ x &=& 3 \quad \text{and }\\ y =f(x) &=& -2 \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (1) & y &=& -2x+4 \qquad & | \qquad x = 3 \\ & y &=& -2\times 3 +4 \\ & y &=& -6 +4 \\ & y &=& -2 \qquad \qquad \mathbf{\text{Yes } y = f(x) = -2} \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (2) & f(x)&=&-x+2 \qquad & | \qquad x = 3 \\ & f(x) &=& -3+2\\ & f(x) &=& -1 \qquad \qquad \text{No } f(x) = -1 \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (3) & f(x)&=&-23x \qquad & | \qquad x = 3 \\ & f(x) &=& -23\times 3\\ & f(x) &=& -69 \qquad \qquad \text{No } f(x) = -69 \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (4) & f(x)&=&3x-2 \qquad & | \qquad x = 3 \\ & f(x) &=& 3\times 3 -2 \\ & f(x) &=& 9 -2 \\ & f(x) &=& 7 \qquad \qquad \text{No } f(x) = 7 \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (5) & f(x)&=&4x+11 \qquad & | \qquad x = 3 \\ & f(x) &=& 4\times 3 +11 \\ & f(x) &=& 12 +11 \\ & f(x) &=& 23 \qquad \qquad \text{No } f(x) = 23 \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline (6) & f(x)&=&6x-20 \qquad & | \qquad x = 3 \\ & f(x) &=& 6\times 3 -20 \\ & f(x) &=& 18 -20 \\ & f(x) &=& -2 \qquad \qquad \mathbf{\text{Yes } y = f(x) = -2} \\ \hline \end{array}$