Why does it say (4^(3/4))^(2/3)/(4^-(5/3))^(3/2)= 64.0000000000000069 ?

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Guest Dec 17, 2014

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Best Answer

(4^(3/4))^(2/3)/(4^-(5/3))^(3/2)

Step by step

The numerator is (4^(3/4))^(2/3) = 4^(1/2) = 2 ...so....

2 / (4^-(5/3))^(3/2) = 2 / 4^(-5/2) = 2 * 4^(5/2) = 2 * [4^(1/2)] ^5 = 2 *[2]^5 = 2 * 32 = 64

(The calculator is definitely a victim of "rounding," here......!!!)

CPhill Dec 17, 2014

CPhill · Answer 1 · 2014-12-17T11:20:21

(4^(3/4))^(2/3)/(4^-(5/3))^(3/2)

Step by step

The numerator is (4^(3/4))^(2/3) = 4^(1/2) = 2 ...so....

2 / (4^-(5/3))^(3/2) = 2 / 4^(-5/2) = 2 * 4^(5/2) = 2 * [4^(1/2)] ^5 = 2 *[2]^5 = 2 * 32 = 64

(The calculator is definitely a victim of "rounding," here......!!!)