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avatar+377 

how would I do:

 

\( \sqrt{432} + \sqrt{675} - \sqrt{300}\)

 

Thanx a lot...

 Nov 9, 2017
 #1
avatar+27529 
+3

First factor the three integers to see that:

 

\(432=3*12^2\\675=3*15^2\\300=3*10^2\\\text{so:}\\\sqrt{432}=12\sqrt3\\\sqrt{675}=15\sqrt3\\\sqrt{300}=10\sqrt3\)

 

You can take it from here.

 Nov 9, 2017
 #2
avatar+377 
+2

thanx Alan,

 

this helps me tremendously...thank you..

juriemagic  Nov 9, 2017

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