how would I do:
\( \sqrt{432} + \sqrt{675} - \sqrt{300}\)
Thanx a lot...
First factor the three integers to see that:
\(432=3*12^2\\675=3*15^2\\300=3*10^2\\\text{so:}\\\sqrt{432}=12\sqrt3\\\sqrt{675}=15\sqrt3\\\sqrt{300}=10\sqrt3\)
You can take it from here.
thanx Alan,
this helps me tremendously...thank you..
+1124 
