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Two boys have $33 in cash between them. One gives $6 to the other and finds he now has twice as much money as his friend. Form an equation by letting $x be the amount one boy had at the start. Hence find how much each boy has now.

Guest Oct 18, 2018

Best Answer 

 #1
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Let 1st boy's money =x
The 2nd boy's money =33 - x
x - 6 =2(33 - x + 6), solve for x
x  - 6 = 66 - 2x + 12
x + 2x =66 + 12 + 6
3x = 84
x =84 / 3
x =$28 - what the 1st boy had.
33 - 28 =$5 - what the 2nd boy had.
Check: $28 - $6 =$5 + $6
                       $22 = $
11 or what the 2 boys have now.

Guest Oct 18, 2018
edited by Guest  Oct 18, 2018
 #1
avatar
+1
Best Answer

Let 1st boy's money =x
The 2nd boy's money =33 - x
x - 6 =2(33 - x + 6), solve for x
x  - 6 = 66 - 2x + 12
x + 2x =66 + 12 + 6
3x = 84
x =84 / 3
x =$28 - what the 1st boy had.
33 - 28 =$5 - what the 2nd boy had.
Check: $28 - $6 =$5 + $6
                       $22 = $
11 or what the 2 boys have now.

Guest Oct 18, 2018
edited by Guest  Oct 18, 2018

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