+0  
 
0
484
1
avatar

We need some help evaluating:      sin[arctan (3^1/2)] ÷ cos[arccot (3^1/2)]

Can you lend a hand? Much appreciated!

 Mar 7, 2016
 #1
avatar+130518 
0

sin(arctan√3)  / cos (arccot √3)  =

 

In the  numberator, arctan √3   =  60°

In the denominator, arccot √3  = 30°

 

So......

 

sin(60°) / cos(30°)  =

 

[ √3/2 ] / [√3/2] =

 

1         [  ......believe it, or not....  !!!!   ]

 

 

 

cool cool cool

 Mar 7, 2016

0 Online Users