write the equation and sketch a circle with a center at (4,6) and that passes through the point (10,11)

Question

0

513

1

Guest Feb 5, 2015

+130511

+5

Best Answer

Let's find the radius, first....this is given by √[(10-4)^2 + (11-6)^2 ] = √[36 + 25] = √61

So we have

(x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center

(x - 4)^2 + (y - 6)^2 = 61

CPhill Feb 5, 2015

CPhill · Answer 1 · 2015-02-05T11:00:00

Let's find the radius, first....this is given by √[(10-4)^2 + (11-6)^2 ] = √[36 + 25] = √61

So we have

(x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center

(x - 4)^2 + (y - 6)^2 = 61