Which pair of parenthese can be removed without changing the value of the expression (1+2)x(6-3)+(5x8) divided by(9-4)
+1904 None of the parentheses can be removed without changing the value of the expression. If you keep the parentheses where they are you get:
\((1+2)\times(6-3)+\frac{5\times8}{9-4}\)
\(3\times(6-3)+\frac{5\times8}{9-4}\)
\(3\times3+\frac{5\times8}{9-4}\)
\(3\times3+\frac{40}{9-4}\)
\(3\times3+\frac{40}{5}\)
\(9+\frac{40}{5}\)
\(9+8\)
\(17\)
If you take out the parentheses around the \(9-4\) you get:
\((1+2)\times(6-3)+\frac{5\times8}{9}-4\)
\(3\times(6-3)+\frac{5\times8}{9}-4\)
\(3\times3+\frac{5\times8}{9}-4\)
\(3\times3+\frac{40}{9}-4\)
\(9+\frac{40}{9}-4\)
\(\frac{81}{9}+\frac{40}{9}-4\)
\(\frac{121}{9}-4\)
\(\frac{121}{9}-\frac{36}{9}\)
\(\frac{85}{9}\)
\(9.4444444444444444...\)
\(17≠ 9.4444444444444444...\)
