$x^2+px+q=0$ has one negative solution and one positive solution. Which of following statements must be true?
(A) $p$ must be positive.
(B) $p$ must be negative.
(C) $q$ must be positive.
(D) $q$ must be negative.
Thanks for helping!
p could be positive or negative
q must be negative ...it is the product (x-a)(x+b) q would equal - ab a negative number
p would equal -a + b and could be either pos or neg