+0  
 
0
101
1
avatar

$x^2+px+q=0$ has one negative solution and one positive solution. Which of following statements must be true?

 

(A) $p$ must be positive.

(B) $p$ must be negative.

(C) $q$ must be positive.

(D) $q$ must be negative.

 

Thanks for helping!

 Nov 4, 2020
 #1
avatar
+1

p could be positive or negative

q must be negative ...it is the product     (x-a)(x+b)    q would equal  - ab    a negative number

                                    p would equal -a + b and could be either pos or neg

 Nov 19, 2020

23 Online Users

avatar
avatar