If you dont already know i is the number mathmeticians use as the answer for the problem sqrt(-1)

But i was wondering if you could use it as an exponent. My thinking is that if you set x^i=4 then take the i root of both sides

x=i*sqrtroot(4) then square both sides x^2=-1*4 symplify, x^2=-4 take the sqare root of both sides x=2i. but i might be wrong. plz it is bugging me to know.

Guest Mar 1, 2017

1+0 Answers


No, it is not that simple!!.


x^i = 4, solve for x

x=4^(-i) * e^(2.Pi.n) !!!.

Guest Mar 1, 2017

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