Expand $-(3-c)(c+2(3-c))$.
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\({\color{BrickRed}-(3-c)(c+2(3-c))} \\ =(c-3)(c+6-2c)\\ =c^2+6c-2c^2-3c-18+6c\)
\(-(3-c)(c+2(3-c))=-c^2+9c-18 \)
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