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0  1 1 2 3 5 8 13 21 is the fibbonacci sequence

What is x+1/x , If x^2+1/x^2=62 ??

(x + 1/x) (x + 1/x)  =

(x + 1/x)^2  =   expand this

x^2 + 2 +   1/x^2    rearrange as

x^2 + 1/x^ 2 + 2     substitute

62 + 2   =

64

Therefore 

(x + 1/x)^2  = 64      take the square root of both sides

x + 1/x   = ±√64  =  ± 8

Solve for x:
x^2+1/x^2 = 62

Bring x^2+1/x^2 together using the common denominator x^2:
(x^4+1)/x^2 = 62

Multiply both sides by x^2:
x^4+1 = 62 x^2

Subtract 62 x^2 from both sides:
x^4-62 x^2+1 = 0

Substitute y = x^2:
y^2-62 y+1 = 0

Subtract 1 from both sides:
y^2-62 y = -1

Add 961 to both sides:
y^2-62 y+961 = 960

Write the left hand side as a square:
(y-31)^2 = 960

Take the square root of both sides:
y-31 = 8 sqrt(15) or y-31 = -8 sqrt(15)

Add 31 to both sides:
y = 31+8 sqrt(15) or y-31 = -8 sqrt(15)

Substitute back for y = x^2:
x^2 = 31+8 sqrt(15) or y-31 = -8 sqrt(15)

Take the square root of both sides:
x = sqrt(31+8 sqrt(15)) or x = -sqrt(31+8 sqrt(15)) or y-31 = -8 sqrt(15)

31+8 sqrt(15) = 16+8 sqrt(15)+15 = 16+8 sqrt(15)+sqrt(15)^2 = (4+sqrt(15))^2:
x = 4+sqrt(15) or x = -sqrt(31+8 sqrt(15)) or y-31 = -8 sqrt(15)

31+8 sqrt(15) = 16+8 sqrt(15)+15 = 16+8 sqrt(15)+sqrt(15)^2 = (4+sqrt(15))^2:
x = 4+sqrt(15) or x = -4+sqrt(15) or y-31 = -8 sqrt(15)

Add 31 to both sides:
x = 4+sqrt(15) or x = -4-sqrt(15) or y = 31-8 sqrt(15)

Substitute back for y = x^2:
x = 4+sqrt(15) or x = -4-sqrt(15) or x^2 = 31-8 sqrt(15)

Take the square root of both sides:
x = 4+sqrt(15) or x = -4-sqrt(15) or x = sqrt(31-8 sqrt(15)) or x = -sqrt(31-8 sqrt(15))

31-8 sqrt(15) = 16-8 sqrt(15)+15 = 16-8 sqrt(15)+sqrt(15)^2 = (4-sqrt(15))^2:
x = 4+sqrt(15) or x = -4-sqrt(15) or x = 4-sqrt(15) or x = -sqrt(31-8 sqrt(15))

31-8 sqrt(15) = 16-8 sqrt(15)+15 = 16-8 sqrt(15)+sqrt(15)^2 = (4-sqrt(15))^2:
Answer: |x = 4+sqrt(15)   or x = -4-sqrt(15)   or x = 4-sqrt(15)   or x = -4-sqrt(15)

Solve for x:
x^2+1/x^2 = 62

Bring x^2+1/x^2 together using the common denominator x^2:
(x^4+1)/x^2 = 62

Multiply both sides by x^2:
x^4+1 = 62 x^2

Subtract 62 x^2 from both sides:
x^4-62 x^2+1 = 0

Substitute y = x^2:
y^2-62 y+1 = 0

Subtract 1 from both sides:
y^2-62 y = -1

Add 961 to both sides:
y^2-62 y+961 = 960

Write the left hand side as a square:
(y-31)^2 = 960

Take the square root of both sides:
y-31 = 8 sqrt(15) or y-31 = -8 sqrt(15)

Add 31 to both sides:
y = 31+8 sqrt(15) or y-31 = -8 sqrt(15)

Substitute back for y = x^2:
x^2 = 31+8 sqrt(15) or y-31 = -8 sqrt(15)

Take the square root of both sides:
x = sqrt(31+8 sqrt(15)) or x = -sqrt(31+8 sqrt(15)) or y-31 = -8 sqrt(15)

31+8 sqrt(15) = 16+8 sqrt(15)+15 = 16+8 sqrt(15)+sqrt(15)^2 = (4+sqrt(15))^2:
x = 4+sqrt(15) or x = -sqrt(31+8 sqrt(15)) or y-31 = -8 sqrt(15)

31+8 sqrt(15) = 16+8 sqrt(15)+15 = 16+8 sqrt(15)+sqrt(15)^2 = (4+sqrt(15))^2:
x = 4+sqrt(15) or x = -4+sqrt(15) or y-31 = -8 sqrt(15)

Add 31 to both sides:
x = 4+sqrt(15) or x = -4-sqrt(15) or y = 31-8 sqrt(15)

Substitute back for y = x^2:
x = 4+sqrt(15) or x = -4-sqrt(15) or x^2 = 31-8 sqrt(15)

Take the square root of both sides:
x = 4+sqrt(15) or x = -4-sqrt(15) or x = sqrt(31-8 sqrt(15)) or x = -sqrt(31-8 sqrt(15))

31-8 sqrt(15) = 16-8 sqrt(15)+15 = 16-8 sqrt(15)+sqrt(15)^2 = (4-sqrt(15))^2:
x = 4+sqrt(15) or x = -4-sqrt(15) or x = 4-sqrt(15) or x = -sqrt(31-8 sqrt(15))

31-8 sqrt(15) = 16-8 sqrt(15)+15 = 16-8 sqrt(15)+sqrt(15)^2 = (4-sqrt(15))^2:
Answer: |x = 4+sqrt(15)   or x = -4-sqrt(15)   or x = 4-sqrt(15)   or x = -4-sqrt(15)

y = x^2 - 12x + 33

Solve for x:
2 x^2 = x+1

Subtract x+1 from both sides:
2 x^2-x-1 = 0

The left hand side factors into a product with two terms:
(x-1) (2 x+1) = 0

Split into two equations:
x-1 = 0 or 2 x+1 = 0

Add 1 to both sides:
x = 1 or 2 x+1 = 0

Subtract 1 from both sides:
x = 1 or 2 x = -1

Divide both sides by 2:
Answer: |x = 1                 or                     x = -1/2

Look under your first post!!.

How would I do (1.26*10^4kg^)+(2.5*106g) in kg?

First convert:(2.5*106g) to Kg.

(2.5*106g) / 1,000 =2.5 x 10^3 Kg.

(1.26*10^4kg + (2.5 x 10^3kg)

=15,100kg =1.51 x 10^4kg

How would I do (1.26*10^4kg^)+(2.5*106g) in kg?

First convert:(2.5*106g) to Kg.

(2.5*106g) / 1,000 =2.5 x 10^3 Kg.

(1.26*10^4kg + (2.5 x 10^3kg)

=15,100kg =1.51 x 10^4kg

I would change #4 to 'keyboarding'  ,  but I hate making suggestions.

Area of a circle is    pi x r^2

3.14  x  (5^2)  =  3.14 X 25 = 78.5  SQUARE CENTIMETERS   also written as  78.5 cm^2

\(Area = \pi {r}^{2} \)

So you do:

\(25\pi = 78.539816339744831{cm}^{2}\)

Good

0.0001 yoctometer

Nothing I know of....but it will be in the dimension of 'units'^3

Maybe THIS is for what you are looking?

d= diameter = 2r    and r = 1/2 d

(1/2d)^2  x  d  = 1/4 d^2 x d = 1/4 d^3

or    r^2 x 2r = 2 r^3  

Just google it!.

Factor the following:
3 x^3+4 x^2-13 x+6

The possible rational roots of 3 x^3+4 x^2-13 x+6 are x = ±1/3, x = ±2/3, x = ±1, x = ±2, x = ±3, x = ±6. Of these, x = 2/3, x = 1 and x = -3 are roots. This gives 3 x-2, x-1 and x+3 as all factors:
Answer: |(3 x-2) (x-1) (x+3)

10/3   x   5   =  50/3  = 16 2/3

(m^3)*(m^6) Plug in 'm' into that equasion to solve!

m^3 x m^6 = m^(3+6) = m^9

What English Dictionary did you use? There is no such word as "paliers" in English that I can find!. What is your native language?.

P.S. Both [ ] and ( ) mean exactly the same thing, even though, sometimes, ( ) are peformed first, then the [ ].

(r^2)d? Well, get the diameter of thecircle, and plug it into the 'd' part. I dont know what 'r' is, but it usually refers to the radius of the circle. What value are you trying to find and what information do you have?

Mathematics uses letters (Variables) to show an unknown value, usuallyone that needs to be solved for. You cant be saved from this unless you skip math altogether, it doesnt just stop. Variables have an important part in math!

(10/3)*5 = 1.25

1.60934 kilometers per mile, please use Google Search for this