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(2a+3b)^3

Take the Inverse sine or sin^-1 of 0.955,

So, theta=sin^-1(0.955) =~72.75 degrees.

if i subtract -12-(-20) is the answer of that will be positive?

Yes!.

-12 + 20 =+8 

Hello gothchick!

(2a+3b)^3

\((2a+3b)^3 = (2a+3b)^2 \times (2a+3b)\) 

\((2a+3b)^3= (4a^2+12ab+9b^2) \times (2a+3b)\)

\((2a+3b)^3 \) 

  = \(8a^3+12a^2b+24a^2b+36ab^2+18ab^2+27b^3\) 

\((2a+3b)^3 =\)  \(8a^3+36a^2b+54ab^2+27b^3\)

Greeting asinus :- )   !

I think you might mean one of the following:

The floor function:  \(\lfloor 2x/3 \rfloor + 3\)

or the ceiling function:  \(\lceil 2x/3 \rceil + 3\)

where the floor function is the nearest integer below the value of the argument and the ceil function is the nearest integer above the value of the argument.  Notice that the lines are not [ or ]; i.e. they are not the same as standard square brackets.

In the graph below f(x) is the floor function and g(x) is the ceiling function:

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Thank you Alan!

If x is a positive integer then -x is negative.  If x is a negative integer then -x is positive.

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This looks like a conversion from degrees Celsius to degrees Fahrenheit

F(C) = (9/5)C + 32

So 60°C  is  (9/5)*60 + 32 → 140°F

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Good morning Guest!

Can someone help me on this problem? Thank you 

1.

y = (x - 2)² + 4

2.

y = - 3x²

3.

y = - 1(x + 3)² + 5

4.

y = - 2(x + 1)² - 3                                          Greetings asinus :- )   !

8^x=16

\(8^x=16\) 

\( \)\(x \times ln8 = ln16\)

\(x= \frac {ln16}{ln8}\) 

\(x=1\frac {1}{3}\)

If x is an integer, then - x is positive. Is this true or false. If false, give a counterexample.

{nl} This is wrong. {nl} All numbers with a minus in front of it are negative.

counterexample:

x = 3 is a positive integer.  x = - 3.1 is a negative real number.

asinus :- )   !

What is the difference of the expression (10b-12+17a) and (7b+5+3a)

(10b - 12 + 17a) - (7b + 5 + 3a)

= 10b - 12 + 17a - 7b - 5 - 3a

= 3b - 17 + 14a   This is the difference.

asinus :- )   !

I'd say start with laying your work out and doing this problem step by step and laying out these steps also don't loose tract of which step your up to and how to do it.

(10^10^100)^2 =10^10^100.30103.....

A positive value equivalent to 10 in the Western-Arabic numeral system. Always make sure to ask your parents' permission before going online! RIP Harambe

(8n)^3 = (8n)(8n)(8n) = 512n^3

1/6(y) + 4/3

I don't know, because I didn't write the problem.

It is true that 4! = 24, but so is a·b·c·d.

2ⁿ  =  1 000 000 000

log( 2ⁿ )  =  log( 1 000 000 000 )

n · log( 2)  =  log( 1 000 000 000 )

n  =  log( 1 000 000 000 ) /  log( 2 )

n  =  29.897...

2²⁹  =  536 870 912

2³⁰  =  1 073 741 824

So, 2³⁰ is closest to 1 000 000 000   --->   n = 30

one: this is a calculator website 

and two: this is one of the most simplist math problems ever

5+5 = 2(5) = 5+5 = (1+1+1+1+1) + (1+1+1+1+1) =/= 1+1+1+1+1+1+1+1+1+1 =/= (1+1) + (1+1) + (1+1) + (1+1) + (1+1) = 5(2)

5+5 =/= 5(2) = 2+2+2+2+2 = (1+1) + (1+1) + (1+1) + (1+1) + (1+1) =/= 1+1+1+1+1+1+1+1+1+1 =/= (1+1+1+1+1) + (1+1+1+1+1) = 5+5 = 2(5)

Thats what they teach in common core!

12r - 8 - 12

12r - 20