Well, just sub 1, 2, 3, 4, 5, 6 for n in each formula, and that will give you the first 6 terms:
a(n) =n^2 - 1
a(1) =1^2 - 1 =1 - 1 =0 that is your first term.
a(2) =2^2 -1 =4 - 1 =3 that is your second term
a(3) =3^2 - 1 =9 -1 =8 that is your third term
a(4) =4^2 - 1 =16 -1=15 that is your fourth term
a(5) =5^2 -1 =25 - 1 =24 that is your fifth term
a(6) =6^2 - 1 =36 -1 =35 and that is your sixth term.
Do exactly the same in the second formula:
a(n) =2*n^3 - 2*n, sub 1, 2, 3, 4, 5, 6 for n
a(1) =2* 1^3 - 2* 1=2 - 2 =0 your 1st. term
a(2) =2* 2^3 - 2*2=16 - 4 =12 your 2nd term.
a(3) =2* 3^3 - 2*3 =54 - 6 =48 your 3rd term
a(4) =2*4^3 - 2*4 =128 - 8 =120 your 4th term
a(5) =2* 5^3 - 2*5 =250 - 10 =240 your 5th term
a(6) =2* 6^3 - 2*6 =432 - 12 =420 your 6th term
Do exactly the same in the third formula:
a(n) =n^2 + n/2 sub 1, 2, 3, 4, 5, 6 for n
a(1) =1^2 + 1/2 =1 1/2 your 1st term
a(2) =2^2 + 2/2 =4 + 1 =5 your 2nd term
a(3) =3^2 + 3/2 =9 + 1 1/2 =10 1/2 your 3rd term
a(4) =4^2 + 4/2 =16 + 2 =18 your 4th term
a(5) =5^2 + 5/2 =25 + 2 1/2 =27 1/2 your 5th term
a(6) =6^2 + 6/2 =36 + 3 =39 your 6th term.
AND THAT IS IT !!. DO YOU UNDERSTAND IT??. CHECK MY MATH TO MAKE SURE I DIDN'T MAKE ANY MISTAKES.
right back at you
