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Um, I guess a is the total, and 3400t is the amount per time, and we have a starting base at 600...

Yah, the wording of the question is a bit unclear...and we both interpreted/read it differently....sorry for the confusion! 

Hmm im not sure myself . Both seem as if they could possibly work but there must be a word that differentes it to being the answer. I will try reading it over using both of yours explanations if you guys end up finding which one is correct could you guys let me know?

Try this, Jenny.....but I don't know....EP's interpretation may actually be correct.....!!!!

I cannot see Chris's graph , is it the same answer but different interperation as you had said ?

im quite unsure who is correct here.

Here is a pretty picture !  

For some reason the graph is not showing with the link

Number 2  (using sine function)

I think the amplitude is   up 5   and down 5 from the midline     Amplitude = 5   (Chris has a different interpretation)

5 sin ?x         period is 32 seconds     2pi/32 = 1/16 pi

5 sin( 1/16 pi x)      and it is shifted UP 8 meters    

5 sin (1/16 pi x) + 8     SHould fit the bill !

For the second one, the first sentence is a little confusing.....I'm assuming that  the amplitude is 5 meters...and the midline is 8 metrers below the water's surface....thus the highest point of the buoy is  3 meters below the surface of the water and the low point is  13 meters below the water's surface

Here's the graph : https://www.desmos.com/calculator/6umbpfydcn

It's all part of learning!   Keep at it .....

thx, I really didn't understand this easy problem. I feel pretty dumb.

x+1 > x-3-x      Are you sure you posted this problem correctly?

x+1 > x - x - 3   The x's on the right 'cancel out'

x+1 > -3             Now subtract 1 from both sides of the equation

x > -4

It is what it is     4009.5    rounded to nearest tenth......without a numeral in the 100th place, you cannot change it.

Here is a graph (with sin function) :    object starts at its highest position at t= 0     takes 20 sec for full cycle

Thanks, EP

Note Jenny :  If you have to use the sine function, here's a possibility :

https://web2.0calc.com/api/ssl-img-proxy?src=%2Fimg%2Fupload%2Fc3c1e3de963ed0ca9b1000f1%2Fgraph.png

Period = 20 seconds (given)       Frequency = 1/period = 1/20

Starts at its highest point = cosine function

resting point = x axis (given)

Amplitude = 6/2 = 3   (1/2 of the height of the 'wave')

3 cos x    has  period of 2pi     to get period of 20   :    2pi/? = 20     then   ? = 2pi/20 =.1 pi

3 cos (1/10 * pi * x) 

Sorry....I see Chris has pointed out that you may need to use the sine function....we will need to shift the curve 1/4 period to the left

20 sec * 1/4 = 5

3 sin (1/10 pi (x+5)) 

fixed it

the multiplication and division is pretty much 0, the its just 67896986898976897698678969568446568.

LOLOLOLOLOLOL

Your explnatation has helped thank you very much

Most of these questions I ask on here are much more easier then they look even more easier the way you explained it .

i had it at the start, but i dont have it now, i think if you register long enough, it will go away after like 3-4 days

it reaches its full rotation after the wavelength number of seconds, or 35-15 or 20 seconds, so the answer is 10/20 * 360 degrees or 180 degrees.

HOPE THIS HELPED!