gibsonj338

None of the parentheses can be removed without changing the value of the expression.  If you keep the parentheses where they are you get:

\((1+2)\times(6-3)+\frac{5\times8}{9-4}\)

\(3\times(6-3)+\frac{5\times8}{9-4}\)

\(3\times3+\frac{5\times8}{9-4}\)

\(3\times3+\frac{40}{9-4}\)

\(3\times3+\frac{40}{5}\)

\(9+\frac{40}{5}\)

\(9+8\)

\(17\)

If you take out the parentheses around the \(9-4\) you get:

\((1+2)\times(6-3)+\frac{5\times8}{9}-4\)

\(3\times(6-3)+\frac{5\times8}{9}-4\)

\(3\times3+\frac{5\times8}{9}-4\)

\(3\times3+\frac{40}{9}-4\)

\(9+\frac{40}{9}-4\)

\(\frac{81}{9}+\frac{40}{9}-4\)

\(\frac{121}{9}-4\)

\(\frac{121}{9}-\frac{36}{9}\)

\(\frac{85}{9}\)

\(9.4444444444444444...\)

\(17≠ 9.4444444444444444...\)

There are two ways to interpret this problem.

First interpret way:

\(\frac{-5}{{6}^{3}}\)

\(-\frac{5}{{6}^{3}}\)

\(-\frac{5}{216}\)

\(-0.0231481481481481...\)

Second interpert way:

\(({\frac{-5}{6}})^{3}\)

\(-({\frac{5}{6}})^{3}\)

\(-\frac{125}{216}\)

\(-0.5787037037037037...\)

\(\frac{a}{d}+\frac{b}{d}\)

\(\frac{a+b}{d}\)

\(\frac{11}{12}-\frac{11}{20}\)

\(\frac{55}{60}-\frac{33}{60}\)

\(\frac{22}{60}\)

\(\frac{11}{30}\)

\(y=2\times(1-{x}^{2})\)

\(y=2-{2x}^{2}\)

\(y={-2x}^{2}+2\)

x-intercepts:

\(0=-{2x}^{2}+2\)

\(-2={-2x}^{2}\)

\(1={x}^{2}\)

\(±1=x\)

\(x=±1\)

\(x=1\) and \(x=-1\)

\((1,0)\) and \((-1,0)\)

y-intercept:

\(y=-{2(0)}^{2}+2\)

\(y=-2(0)+2\)

\(y=0+2\)

\(y=2\)

\((0,2)\)

Graph:

\(\frac{2}{3n}-\frac{2}{3}=\frac{n}{6}+\frac{4}{3}\)

\(\frac{6}{9n}-\frac{6n}{9n}=\frac{n}{6}+\frac{4}{3}\)

\(\frac{6-6n}{9n}=\frac{n}{6}+\frac{4}{3}\)

\(\frac{6-6n}{9n}=\frac{2n}{12}+\frac{16}{12}\)

\(\frac{6-6n}{9n}=\frac{2n+16}{12}\)

\(6-6n=\frac{9n\times(2n+16)}{12}\)

\(6-6n=\frac{3n\times(2n+16)}{4}\)

\(4\times(6-6n)=3n\times(2n+16)\)

\(24-24n=3n\times(2n+16)\)

\(24-24n={6n}^{2}+48n\)

\(24={6n}^{2}+72n\)

\(4={n}^{2}+12n\)

\(40={n}^{2}+12n+36\)

\(40={(n+6)}^{2}\)

\(±2\sqrt{10}=n+6\)

\(-6±2\sqrt{10}=n\)

\(n=-6±2\sqrt{10}\)

\(n=-6+2\sqrt{10};\)  \(n≈ 0.3245553203367587\)

\(n=-6-2\sqrt{10};\)  \(n≈-12.3245553203367587\)

\(-(2+2m)-2>6\)

\(-2-2m-2>6\)

\(-4-2m>6\)

\(-2m>10\)

\(m<-5\)

That is correct.

You mean \(300?\)  \(300!\) is equal to 1*2*3*4*5*6*7*8*9*10*11*12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28*29*30*31*32*33*34*35*36*37*38*39*40*41*42*43*44*45*46*47*48*49*50*51*52*53*54*55*56*57*58*59*60*61*62*63*64*65*66*67*68*69*70*71*72*73*74*75*76*77*78*79*80*81*82*83*84*85*86*87*88*89*90*91*92*93*94*95*96*97*98*99*100*101*102*103*104*105*106*107*108*109*110*111*112*113*114*115*116*117*118*119*120*121*122*123*124*125*126*127*128*129*130*131*132*133*134*135*136*137*138*139*140*141*142*143*144*145*146*147*148*149*150*151*152*153*154*155*156*157*158*159*160*161*162*163*164*165*166*167*168*169*170*171*172*173*174*175*176*177*178*179*180*181*182*183*184*185*186*187*188*189*190*191*192*193*194*195*196*197*198*199*200*201*202*203*204*205*206*207*208*209*210*211*212*213*214*215*216*217*218*219*220*221*222*223*224*225*226*227*228*229*230*231*232*233*234*235*236*237*238*239*240*241*242*243*244*245*246*247*248*249*250*251*252*253*254*255*256*257*258*259*260*261*262*263*264*265*266*267*268*269*270*271*272*273*274*275*276*277*278*279*280*281*282*283*284*285*286*287*288*289*290*291*292*293*294*295*296*297*298*299*300 which is a very large number no oridinary calculator can calculate.

\(75+25+100+50+50\)

\(100+100+50+50\)

\(200+50+50\)

\(250+50\)

\(300\)