Melody

I keep sorting them into two groups until there is only one in each group.

Like for instance

5, -4,  0.6,  0.1,  11/12

First negs are smaller than pos so -4 is in one pile and the rest in another

-4,              5,  0.6,  0.1,  11/12

 Now I can see that 5 is the biggest it is the only one greater than 1

-4,              0.6,  0.1,  11/12                  5

Now I would split them into more than 1/2 and less than 1/2.   0.1 is the only one less than 1/2

-4,              0.6,  0.1,  11/12                  5

-4,   0.1,                 0.6,  11/12                         5

Now 11/12 is almost 1 and 0.6 is only a bit more than 1/2   so the answer is 

-4,      0.1,       0.6,     11/12       5

If there are any that are really close together you can use a calc to change them to decimals and you should know how to place decimals in order!

3y^2+31y+36

I am sorry guest but your answer is NOT correct.

There is no equal sign here, this is NOT an equation.  So you have answered a different question entirely!

The question is, how do you factor    \(3y^2+31y+36\).

What you need to look for is two numbers that multiply to 3*36  and add to 31

Since both these numbersare positive, both the numbers that you are looking for will also be positive.

Factors of 3*36 

=3*3*12

=3*3*3*4

=3*3*3*2*2

=  27 * 4

and 27+4=31 so these are the numbers that I want.

So now I have to repleace  31y   with    27y+4      like this

\(\quad3y^2+31y+36\\ =​​​​3y^2+27y+4y+36\\ \mbox{Now I have to factor in pairs}\\ =3y(y+9)+4(y+9)\\ =(3y+4)(y+9)\)

If you do not understand say so :))

Yes, that are gone.  It is a pity that some people have so little to do with their time. 

Thanks for bringing it to my attention.  :))

It is really great to see these wonderful answerers from guests.

We would really like you to become members.  There used to be a lot more active members - young ones - and the place was a lot more alive.  If you have names we get to know you and our community develops.  It is good for everyone.  

But, even if you don't become members it  is great thay you are posting good answers :)

Mon 19/10/15

@@ What is Happening?  [Wrap4]    Sun 18/10/15     Sydney, Australia Time 10:00pm   ♪ ♫

Good day to you all.   

Here are the interest posts:

Thanks Alan,  I still like my graph.             

I need to look at your number 2 answer properly :))

There is a calculator on the home page :)

x^2+12x+39

What about it?

It cannot be factored.  (not within the real number system anyway)

A loan company charges 20 dollars interest for a two month loan of 325 dollars. Find the annual interest rate (APR) they are charging. Round interest to tenth of a percent.

I have a loan formula, would I use that to find R?

Mmm

It would depend on how often they add interest to the principal, that is , what is the compounding period.......

but

20/325= 6.1538461%

so nominal annual interest rate may be  6*6.1538461%=36.9230769% = 36.9%

I'm not borrowing any money off them!!