Melody

How can y=7 if y=6        LOL

I think there is info missing here  :))

-3--25= - 3 + 25 = 22

assuming degrees

arccos(cos230)

=arccos(-cos(230-180))

=arccos(-cos(50))

=arccos(cos(180-50))

=arccos(cos(130))

=130 degrees

This is what I am imagining is the situation.

Now use Pythagorean theorum.

\((t+20)^2=t^2+(t/2)^2\\ t^2+40t+400=(4t^2+t^2)/4\\ 4t^2+160t+1600=5t^2\\ 0=t^2-160t-1600\\\)

\(x = {160 \pm \sqrt{160^2+4*1600} \over 2}\\ x = 169.4427\)

The height is 169.4 m

It is nice to meet you syakirah159.  

But you need to check this answer.

1.6f - 8.3f = ????

Finallly I am happy with my answer.  

@@ What is Happening?  [Wrap4]   Thurs 19/11/15   Sydney, Australia Time 5:40pm  ♪ ♫

Hello everyone,

We have had many great answers supplied by Heureka, Alan, CPhill, TMga2yb, nicolas0122, bubbleman, rarinstraw1195, LordEnedor, Rom, Saseflower, Omi67, EinsteinJr and Syakirah159. Thanks all.  

Forum Issues:

Mr Massow has replied to my message. He agrees with me that the access problems some people are having is the most important issue at the moment.  He is having trouble reproducing it but that is where his efforts are being directed at the present time.  He said he may be able to address some of the lesser issues over the weekend.

Thank you Mr Massow.  

Interest Posts:

If you ask or answer an interesting question, you can private message the address to me (with copy and paste) and I will include it.  Of course only members are able to do this.  I quite likely will not see it if you do not show me.  

1)  Quarters and nickels

a manufacturer is cutting fabric into rectangles that are 18.55in. long by 36.75in. wide. Each rectangle's length and width must be within 0.05 in. of the desired size. Write and solve inequalities to find the acceptable for the length l and the width w

\(18.50" \le length\le 18.60" \\ 36.7"5-0.05" \le\ width \le 36.75"+0.05"\)

You can tidy up the second one :))

What is the inverse of [2x+1/3]

\(y=2x+1/3\\ y-1/3=2x\\ x=\frac{1}{2}(y-\frac{1}{3})\\ x=\frac{1}{2}(\frac{3y-1}{3})\\ x=\frac{3y-1}{6}\\ \mbox{The inverse is }\\ y=\frac{3x-1}{6}\\\)