Melody

This will help you remember the quadratic formula. 

Thanks Alan - Now 2 people have help me.

I guess I didn't put this big enough. lol

(Thank you - I have received 'spiritual' help. That is, help from a disembodied human)

I love the hover display boxes that andre has added for LaTex and Math display.

It should really help people to learn.  I put a number of Rom's outputs over into the LaTex thread but I mustn't have pressed Publish because they are not there.  I will have to enter them all over again! Drats!

This si the question that GoldenLeaf solved - the x is on the top, NOT on the bottom.   

-4=-7/4x-7+9/4x

-4=(-7/4)x-7+(9/4)x

That is a good answer GoldenLeaf. 

always leave it with the pronumeral on the left

x=6  

Hi GoldenLeaf, thanks for answering, we like everyone to get involved

Oh and welcome to Web2.0calc forum.  We hope you like it her.

Unfortunately what you have done is not correct because the 2 is not meant to be raised to the power of 3.

$$2(-3x^2y^3)^3\\\\
=2\times ((-1)^3\times 3^3\times (x^2)^3\times (y^3)^3)\\\\
=2\times(-1\times 27\times x^6 y^9)\\\\
=-54x^6y^9$$

You could solve it using the quadratic formula.

atan(1/sqrt(x))-atan(sqrt(x)) = 105

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1}}}{{\sqrt{{\mathtt{x}}}}}}\right)}{\mathtt{\,-\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\sqrt{{\mathtt{x}}}}\right)} = {\mathtt{105}} \Rightarrow \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{2\pi}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\sqrt{{\mathtt{x}}}}\right)} = {\frac{\left({\mathtt{12}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{2\pi}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1}}}{{\sqrt{{\mathtt{x}}}}}}\right)}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{\pi}}\right)}{{\mathtt{12}}}}$$

Umm, that doesn't look very helpful does it!

I don't know about a rate but this is the answer1

$${\frac{{\mathtt{1}}}{{\mathtt{4}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{9}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{16}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{25}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{36}}}} = {\frac{{\mathtt{1\,769}}}{{\mathtt{3\,600}}}} = {\mathtt{0.491\: \!388\: \!888\: \!888\: \!888\: \!9}}$$

I just copied you answer, opened the input=result box, pasted the question in, hit equal, and magic - there is your answer.

Did you try to do this on your android GoldenLeaf?

I don't know how to do almost anything on my android.  Stupid thing. lol

I posted a page of latex before and now it is all gone!

I must of forgotten to hit "Publish" I am a drongo!  I'll have to do it again - Later.

(Drongo is Australian slang meaning 'a fool', but when used like this it is light hearted.  

It is also the name of an Australian bird.)

$$e^{ln5}=5$$

Is that what you mean?

100*99 = 9900

or if you prefer

$$^{100}P_2}$$          $${\left({\frac{{\mathtt{100}}{!}}{({\mathtt{100}}{\mathtt{\,-\,}}{\mathtt{2}}){!}}}\right)} = {\mathtt{9\,900}}$$

or

$$2\times^{100}C_2$$          $${\mathtt{2}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{100}}{!}}{{\mathtt{2}}{!}{\mathtt{\,\times\,}}({\mathtt{100}}{\mathtt{\,-\,}}{\mathtt{2}}){!}}}\right)} = {\mathtt{9\,900}}$$

Take your pick!

Can someone please remind me how to put the last 2 answers into the Input=Result.

(Thank you - I have received 'spiritual' help. That is, help from a disembodied human)

I suppose I should look it up but i have the same lazy attitude as many question askers.  It is easier just to ask.