tertre

Ava: 0.14-14/100*50=7 brownies

Grace: 4/50*50=4 brownies

Jayden: 24/100*50=12 brownies

So, Zoe=50-23=27

zoe: 27 brownies

Thus, Zoe stacked the most brownies!

When x=1, y=5, when x=2, y=9, when x=3, y=13, and so on. What is the value of y, when x=10?

Solution:

We know that the difference between y and x is 4, as we can see in our pattern. But, if we look more closely, we can see that 4x+1=y. (1*4+1, 2*2+1=5, 3*4+1=13, and so on). So, to find y when x=10, we simply do 4(10)+1=\(\boxed{41}\)

6. The graph can be found here:

https://www.desmos.com/calculator/x4vl7k5c8z

8.

 Let me take my best shot at it!

30*44=1320

So, 44 people=1320

55 people=1320/55=24, (C)

32.

 numbers greater than 4, or prime numbers.

2,3,5,6

4/6

=2/3

19. Since the pattern is times 3 from the previous number, and we want to find the tenth number, here's the list:

1+3+9+27+81+243+729+2187+6561+19683

Adding gives us:

29524

Calculator: 10 letters

(a) repeats twice

(c) repeats twice

(l) repeats twice 

So, \(\frac{10!}{2!*2!*2!}=453600\)

Combinations!

\({5}\choose{1} \)+\({5}\choose{2}\)+\({5}\choose{3}\)= \(5+10+10=25\)

\({6}\choose{2}\)+\({6}\choose{3}\)+\({6}\choose{4}\)=\(15+20+15=50\)

Thus, \(50*25=\boxed{1250}\)

Plotting this on a piece of paper, and labeling all the points;

We have S midway of 8, which is 4

We have T midway of 6, which is 3

Thus, we have a right angle triangle, and we use this formula:

a^2+b^2=c^2

Plugging 4 for a, and 3 for b, we have

4^2+3^2=c^2

c^2=25

\(c=\boxed{5}\)

st=5, (a)

Here's a similar question: 

https://web2.0calc.com/questions/help_48981