Okay, so:
y=Dx+7
Plug 0 for, and 4 for y:
4=0(D)+7
0D=-3
D=-3/0
If y=Bx+2 goes through (3,10), we can plug 3 for x, and 10 for y:
Doing that, we have: \(10=3B+2\)
\(3B=8, B=\frac{8}{3}\)
Well, I'll answer how many paperbacks he can fit.
Since each paperback is 12ft*15ft*15 ft thick
And, the swimming pool is 40ft*30ft*30ft
We can do:
\(\frac{40*30*5}{12*15*15}=\frac{6000}{2700}=2.22\approx\boxed{2}\)
This is combinations because he can choose any 3 shirts from the 12 total.
We use the formula, \(\frac{n!}{r!*(n-r)!}\)
Plugging the values in, we have: \(\frac{12!}{3!*(9!)}=\frac{12*11*10}{3*2*1}=44*5=\boxed{220}\) ways.
21/15=1.4
So, the similar shapes are 1.4 apart.
But, we have to square 1.4 - 1.4^2=1.96
Thus, we get \(\frac{196}{1.96}=\boxed{100}\) centimeters ^2
The formula to find the area of a circle:\( \pi r^2\)
If we know our diameter is 11, then our radius is 5.5
Thus, \(5.5^2\pi=30.25\pi\)
Okay, \(30.25 \longrightarrow 30\frac{1}{4}=\boxed{\frac{121}{4}}\)
1st figure= 20m, 2nd figure=34m
20:34
1:34/20
Area=19.6
So, 19.6*34/20=\({33.32}=\boxed{33.3}\)
Welcome, CPhill! I like your solution!
45. tan 5pi/6=\(\frac{-\sqrt3}{3}\)
41. cos 300=1/2
