tertre

Stem: The numbers to the left of the line, and Leaf: The numbers to the right of the line.

We have, 28, 28, 50, 1:00, 1:02, 2:20, 2:25, 2:35, 2:43, 2:45, 3:00, 3:00, 3:00, 3:30, 3:36, 4:00, 4:00.

Finding the middle, we get 2 minutes and 43 seconds, so 120+43=163 seconds.

It's the green dot! So, -0.5, (C), the third option. 

Is it the last option? 40

x-50=41, x=91, x-50=59, x=109. So, (D). 

I think it is: 61, 61, 61, 178, 179, and no angle can be < 61 degrees.

First Quartile= Quartile 1, 25, 35, 45, 50, 60, 80, 90, 95, 100- median is 60, 35+45=80/2=40, (A)?

3x+2y=-1, x=2y=5, adding both cancels out y, so we are left with: 4x=-1+5, 4x=4, x=1.

Plugging the value of x in the second equation to solve y, we have 1-2y=5, -2y=4, y=-2.

Check for the first equation: 3(1)+2(-2)=3-4=-1.

We have 3x+2y=−13x+2y=−1 and x−2y=5.

Simplifying the first equation: 3x+2y=-13x+2y, 16x=0y, so 16x=-1, and x=-1/16.

Plugging the value of x in our second equation: \(\frac{-1}{16}-2y=5, -2y=\frac{81}{16}, 2y=\frac{-81}{16}, y=\frac{-81}{32}.\)

We can set up two equations!
1.5c+4a=734 and c+a=281.

We multiply the second equation by 4 but leave the first equation as it is. 

So, 1.5c+4a=734, 4c+4a=1124

Subtract, 1.5c-4c=734-1124, -2.5c=-390, 2.5c=390, c=\(\boxed{156}\)children and 281-156=\(\boxed{125}\) adults. 

The reciprocal of the sum of the two numbers can be written as \(\frac{1}{x}+\frac{1}{y}\)

We have \(x+y=16, \) and \(xy=35\) , so we can find the LCM of \(x\) and \(y\) .

So, we have: \(\frac{x}{xy}+\frac{y}{xy}\) . Adding both fractions, we get,\(\frac{x+y}{xy}\) and plugging in the values we finally attain: \(\boxed{\frac{16}{35}}\) .

Oh, thank you, CPhill! My small error, oops!