Yes; it is. 0 is divisible by any number!
8 team members, 5000 ft., 30 minutes
8 team members, 8000 ft, ?
8 team members, 166 ft , 1 minute
8 team members, 8000 ft, \(\boxed{48}\) minutes, approximately
Oops, then it's 23 handshakes!
Well, I don't know if this is correct, but...
8m*40m=320m^2 and 320 meters is approximately \(320m^2 * (1ft/0.3048m)^2 * (1gal/400ft^2) = 8.611\) galllons( unit conversions) feet, so 9 gallons?
Or, we can just plug the value in the handshake formula: n(n-1)/2, 23*22/2=23*11=253 handshakes!
Look at EP's solutions for more information!
Lol, silly mistake, didn't read the cube sign.......
1. Roosters don't lay eggs!
2. $18, based off on the legs!
3. Lol! The answer is grandfather, father, son, so \(\boxed{3}\) tickets.
We're just plugging in values of \(t.\)
(a): \(9(-3)^3+8(-3)^2-4(-3)-9=-168.\)
So, just plug the values of \(t\), listed in your question, like how I solved it!
Number of People in the wave pool: 430 people
Maximum capacity: 600 people
So, we have the inequality: \(430+x\leq600\), and you can solve for \(x\), if you want to!
First, expand \(2(3- \sqrt3)\) to \(6-2\sqrt3\) , by applying the distributive property, ab-ac.
Next, we expand the second term, \(-3(1- \sqrt3)\) to \(-3+3\sqrt{3}\) , by again using the distributive property.
Finally, we simplify, (by adding similar elements), \(6-2\sqrt{3}-3+3\sqrt{3}\) and that will get us \(\boxed{3+\sqrt{3}}.\)
