We can label x as the number of 7th and 8th graders, and x-50 as the number of 6th graders. So, we have x+x+x-50=3x-50=790 students. Therefore, 3x=840 students and x=280 students. We can solve for x-50, which is 280-50=230. Back again, we have 9/10(x-50)+7/8x+3/5x, which is just 9/10(230)+7/8(280)+3/5(280)=207+245+168=620 students.
If we add 2y to both sides, we get 3x+2y=10-7, 3x+2y=3. Since we are finding for 6x+4y, double both sides of the equation, so 6.
Our keywords: product, increased, quotient
Now, translating this, we have \(5*6+\frac{30}{6}\) .
Yes, it is! The median is constant!
1. Wild guess, is the answer 29?
The negatives cancel out, so we are left with 0.6p=14.4. Convert 0.6p to 6/10p and 14.4 to 14 4/10, if you like. Your answer should be 24.
Original amount: 80 books
1st month: 100 books
2nd month: 125 books
3rd month: 156.25 books
4th month: 195.3125 books
5th month: 244.14 books
6th month: 305.175 books
7th month: 381.46 books
8th month: 476.825 books
9th month: 596.03 books
10th month: 745.03 books
Thus, by the end of the 10th month, \(\boxed{745}\) books are expected to be donated to the library.
Can you post it again? Looks like the image is blocked by a moderator!
Hey, SG here is a short way!
We know that the square root of 25 is 5, so every 5th power should end in the last digit.
Thus, 12^5 ends in a 0, and 8^5 also end in a zero. Now, we have two zeroes and doing some quick computation, we have 0+0=0.
\(4^3 * 5^4 *6^2=2^6*5^4*2^2*3^2=2^8*3^2*5^4.\) There is actually a neat way to calculate the number of factors a number has. Suppose we have \(4^k\) , and the number of factors that number would have is \(4^{k+1}\) . Following the same example here, we have \(9*3*5=27*5=\boxed{135}\) factors.
